Let us multiply the given binomials (2x2−5y2) and (x2+3y2) as shown below:
(2x2−5y2)(x2+3y2)=2x2(x2+3y2)−5y2(x2+3y2)=(2x2×x2)+(2x2×3y2)−(5y2×x2)−(5y2×3y2)=2x4+6x2y2−5x2y2−15y4=2x4+(6x2y2−5x2y2)−15y4(Combiningliketerms)=2x4+x2y2−15y4
Hence, (2x2−5y2)×(x2+3y2)=2x4+x2y2−15y4.