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Question

(2x25y2)×(x2+3y2).

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Solution

Let us multiply the given binomials (2x25y2) and (x2+3y2) as shown below:

(2x25y2)(x2+3y2)=2x2(x2+3y2)5y2(x2+3y2)=(2x2×x2)+(2x2×3y2)(5y2×x2)(5y2×3y2)=2x4+6x2y25x2y215y4=2x4+(6x2y25x2y2)15y4(Combiningliketerms)=2x4+x2y215y4

Hence, (2x25y2)×(x2+3y2)=2x4+x2y215y4.

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