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Question

2x2+7x−1 completely divides 10x4+17x3−62x2+30x−3 .


A

True

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B

False

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Solution

The correct option is A

True


On dividing, we get

5x29x+32x2+7x110x4+17x362x2+30x310x4+35x35x2 + 18x357x2+30x3 18x363x2+9x + + 6x2+21x3 6x2+21x3 + 0

The remainder hence obtained is zero. Therefore 2x2+7x1 divides 10x4+17x362x2+30x3 completely.


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