2^x+2^x+3^x+3^x+3^x = 97
Then 10^x is ?

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Solution

2^x+2^x+3^x+3^x+3^x = 97

which can be written as

22^x + 33^x = 97
2^(x+1)+3^(x+1) = 97

taking log on both sides
2^(x+1)+3^(x+1) = 97

On solving we get x=3 (trail and error)

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