$2 x + 3 y = 1 & 3 x - y = 7$ are ______.

intersecting lines

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parallel lines

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coincident lines

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dependent pair of linear equations

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Solution

The correct option is A intersecting lines
For consistent pair of lines or intersecting lines, $\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}} .$

Here $\frac{2}{3} \neq \frac{3}{- 1} \to$ These are consistent lines.

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Similar questions

3 x - y = 7

2 x + 3 y = 1

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}

\frac{7}{2 x + 3 y} + \frac{4}{3 x - 2 y} = 2

2 x + 3 y \neq 0

3 x - 2 y \neq 0

2 x + 3 y = 7

3 x + 2 y = 3, x - y =

y = 3 x + 5

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}, \frac{7}{(2 x + 3 y)} + \frac{4}{(3 x - 2 y)} = 2

(2 x + 3 y)

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