The given system of equation is:
2x − 3y = 13 .........(i)
7x − 2y = 20 ........(ii)
On multiplying (i) by 2 and (ii) by 3, we get:
4x − 6y = 26 .......(iii)
21x − 6y = 60 ......(iv)
On subtracting (iii) from (iv) we get:
17x = (60 − 26) = 34
⇒ x = 2
On substituting the value of x = 2 in (i), we get:
4 − 3y = 13
⇒ 3y = (4 − 13) = −9
⇒ y = −3
Hence, the solution is x = 2 and y = −3