The correct option is B −5−4x<y<5−4x
Lets look at the given inequality
|12x+3y|<15
We know that if |x|<a, then −a<x<a
Therefore, |12x+3y|<15
−15<12x+3y<15
Subtract 12x from each side
−15−12x<12x+3y−12x<15−12x
−15−12x<3y<15−12x
Divide by 3 on each side
−15−12x3<3y3<15−12x3
−5−4x<y<5−4x
Correct answer is option B.