We have, #10; #10; ( 2x+3y )^2 16z^2 #10; #10; ⇒( 2x+3y )^2 ( 4z #10;)^2 ( ∴A^2 B^2=( A+B )( #10;A B ) ) #10; #10; ⇒( 2x+3y+4z ) ...

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Division of a Polynomial by a Polynomial

2x+3y 2 -16 z...

Question

$(2 x + 3 y)^{2} - 16 z^{2}$

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Solution

We have,

${(2 x + 3 y)}^{2} - 16 z^{2}$

$\Rightarrow {(2 x + 3 y)}^{2} - {(4 z)}^{2} (∴ A^{2} - B^{2} = (A + B) (A - B))$

$\Rightarrow (2 x + 3 y + 4 z) (2 x + 3 y - 4 z)$

Hence, this is the answer.

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