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Question

2x-3y=9,3x+7y=2, y0.

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Solution

The given equations are:
2x-3y=9 ............(i)
3x+7y=2 .............(ii)
Putting 1y=v, we get:
2x − 3v = 9 .............(iii)
3x + 7v = 2 ...........(iv)

On multiplying (iii) by 7 and (iv) by 3, we get:
14x − 21v = 63 .............(v)
9x + 21v = 6............(vi)

On adding (v) and (vi), we get:
23x = 69 ⇒ x = 3

On substituting x = 3 in (i), we get:
2×3-3y=9
6-3y=93y=-3y=-1
Hence, the required solution is x = 3 and y = −1.

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