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Question

2x-5 x2-4x+3 dx

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Solution

Let I= 2x-5 x2-4x+3 dx= 2x-4-1 x2-4x+3 dx=2x-4 x2-4x+3 dx-x2-4x+3 dx=2x-4 x2-4x+3 dx- x2-4x+4-4+3 dx=2x-4 x2-4x+3 dx- x-22-12 dxLet x2-4x+3=t2x-4dx=dtI=t dt-x-22-12 dx=23t32-x-22 x-22-12-122logx-2+x-22-1+C=23x2-4x+332-x-22 x2-4x+3+12log x-2+x2-4x+3+C

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