$2 X + B_{2} H_{6} ⟶ [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}$ the amine(s) X is/are:

$N H_{3}$

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$C H_{3} N H_{2}$

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$(C H_{3})_{2} N H$

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$(C H_{3})_{3} N$

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Solution

The correct option is C
$(C H_{3})_{2} N H$

The reaction:

$2 X + B_{2} H_{6} ⟶ [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}$

Is consistent with X being a non-tertiary amine. As in, ammonia, methylamine and dimethylamine all would definitely give this reaction. However, with a tertiary amine, an adduct is formed:

$2 R_{3} N + B_{2} H_{6} ⟶ 2 H_{3} B (N R_{3})$

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X

$2 X + B_{2} H_{6} ⟶ [B H_{2} (X)_{2}]^{+} [B H_{4}]^{-}$ the amine(s) X is/are:

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