$2 x (4 x - 1) (3 x + 9)$ is equal to

24 x^{3} + 66 x^{2} - 18 x

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20 x^{3} + 68 x^{2} - 16 x

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22 x^{2} + 67 x - 18

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12 x^{3} + 33 x^{2} - 9 x

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Solution

The correct option is C $24 x^{3} + 66 x^{2} - 18 x$
$2 x (4 x - 1) (3 x + 9) = 2 x [(4 x) (3 x) + (4 x) (9) - (1) (3 x) - (1) (9)]$

= $2 x (12 x^{2} + 36 x - 3 x - 9)$

= $2 x (12 x^{2} + 33 x - 9)$

= $(2 x) (12 x^{2}) + (2 x) (33 x) - (2 x) (9)$

= $24 x^{3} + 66 x^{2} - 18 x$

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Question 64

To what expression must $99 x^{3} - 33 x^{2} - 13 x - 41$ be added to make the sum zero?

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