Question

$2x^2-5\sqrt{2}x+4=0$

Answer 1

$$\begin{gathered} \mathrm{Given}: \\ 2x^2-5\sqrt{2x}+4=0 \\ \text{Here,} \\ a=2, \\ b=-5\sqrt{2}, \\ c=4 \\ \mathrm{Discriminant}D\mathrm{is}\mathrm{given}\mathrm{by}: \\ D=b^2-4ac \\ ={(-5\sqrt{2})}^2-4\times 2\times 4 \\ =(\text{25}\times \text{2})-32 \\ =50-32 \\ =18 \end{gathered}$$