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Byju's Answer
Standard IX
Mathematics
Addition of Polynomials
2 × 2-6 x 2-8...
Question
2
x
2
-
6
x
2
-
8
x
2
-
6
x
+
3
-
40
Open in App
Solution
We
have
2
x
2
-
6
x
2
-
8
x
2
-
6
x
+
3
-
40
Substituting
x
2
-
6
x
=
a
,
we
get
:
2
x
2
-
6
x
2
-
8
x
2
-
6
x
+
3
-
40
=
2
a
2
-
8
a
+
3
-
40
=
2
a
2
-
8
a
-
24
-
40
=
2
a
2
-
8
a
-
64
=
2
a
2
-
4
a
-
32
=
2
a
2
-
8
a
+
4
a
-
32
=
2
a
a
-
8
+
4
a
-
8
=
2
a
-
8
a
+
4
Resubstituting
the
value
of
a
,
we
get
:
2
x
2
-
6
x
2
-
8
x
2
-
6
x
+
3
-
40
=
2
x
2
-
6
x
-
8
x
2
-
6
x
+
4
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1
Similar questions
Q.
Factorise :
2
(
x
2
−
6
x
)
2
−
8
(
x
2
−
6
x
+
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)
−
40
Q.
If
x
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2
+
2
2
3
+
2
1
3
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t
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e
n
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−
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Q.
If
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+
2
2
3
+
2
1
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, then
x
3
−
6
x
2
+
6
x
=
Q.
If
x
=
2
+
2
1
/
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+
2
2
/
3
, then
x
3
−
6
x
2
+
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x
=
.............
Q.
If
x
=
2
+
2
2
3
+
2
1
3
then prove that
x
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x
2
+
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=
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