2 x3-2 y3-2 z3-6 x y z-x-y-z-x-y2-y-z2-z-x2- hence evaluate 273-93-2133-67913

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(x±a)(x±b) = x²±(a+b)x+ab.

2 x3+2 y3+2 z...

Question

2x³ +2y³ +2z³- 6xyz= (x+y+z) [(x-y)² +(y-z)² +(z-x)² ] hence evaluate 2(7)³ +(9)³ + 2(13)³ -6(7)(9)(13).

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