$(2 y + 5) (2 y + 5)$ =

4 y^{2} + 10 y + 25

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4 y^{2} + 20 y + 25

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4 y^{2} + 20 y + 15

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y^{2} + 20 y + 25

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Solution

The correct option is B $4 y^{2} + 20 y + 25$
$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
Using the identity,
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5)^{2} = (2 y)^{2} + 2 (2 y) (5) + 5^{2} = 4 y^{2} + 20 y + 25$

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