Given: 2y2 + 11y – 7 = 0
To find the nature of the roots, we need to find the discriminant of the given quadratic equation.
We know that the discriminant of a quadratic equation is Δ = b2 – 4ac.
On comparing the given equation with ay2 + by + c = 0 in variable y, we get:
a = 2, b = 11 and c = –7
Thus,
Δ = (11)2 – 4(2)(–7)
=> Δ = 121 + 56 = 177
Since Δ > 0, the roots of the given quadratic equation are real and unequal.