Note : There must be misprinting in the question .Question must be 2y2 – 7y – 3 = 0 instead of 2x2 – 7y – 3 = 0
Given: 2y2 – 7y – 3 = 0
To find the nature of the roots, we need to find the discriminant of the given quadratic equation.
We know that the discriminant of a quadratic equation is Δ = b2 – 4ac.
On comparing the given equation with ay2 + by + c = 0 in variable y, we get:
a = 2, b = –7 and c = –3.
Thus,
Δ = (–7)2 – 4(2)(–3)
=> Δ = 49 + 24 = 73
Since Δ > 0, the roots of the given quadratic equation are real and unequal.