Question

$2z-\frac{5}{z}=z-6$

Answer 1

Given: $2z-\frac{5}{z}=z-6$

On multiplying both sides by z, we get:

$z\left(2z-\frac{5}{z}\right)=z\left(z-6\right)$

$\Rightarrow$2z² – 5 = z²– 6z

On transposing all the terms of the right-hand side to the left-hand side, we get:

2z² – 5 – z² + 6z = 0

$\Rightarrow$z² + 6z – 5 = 0

Thus, the standard form of the given quadratic equation is z² + 6z – 5 = 0.