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Internal Energy

3.0 moles of ...

Question

$3.0$ moles of ideal gas is heated at constant pressure from $27^{0}$ C to $127^{0}$ C, then calculate the work done in the expansion of a gas.

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Solution

Given that
$T_{i} = 27^{0} C = 300 k p = 3$
$T_{f} = 127^{0} C = 400 K$
$V_{i} = \frac{n R T_{I}}{p}$
$V_{f} = \frac{n R T_{f}}{P}$
Since, work done w= $w = - P V$
$= - P (V_{f} - V_{i})$
$- (\frac{n R}{P}) \times (T_{f} - T_{i}) - (1)$
Putting all given value in equation-(1)
we have,
$w = - 3 \times 8.314 \times (400 - 300)$
$= 2494.25$

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