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Question

3.0×103 kg of acetic acid is added to 500 mL of water. 23% of acetic acid is dissociated. If Kf and density of water are 1.86Kkgmol1 and 0.997 g/mL respectively. The depression in freezing point of acetic acid is :

A
0.227
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B
0.229
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C
0.231
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D
0.233
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Solution

The correct option is B 0.229
We have, ΔT=Kf×molality×(1+α)For acetic acid:CH3COOHCH3COO+H+
1 0 0
1α α α
Given, α=0.23;

Also, molality=mole of acetic acidweight of water in kg
=(3×103×103){60×(500×0.997)103}=0.10ΔT=Kf×molality×(1+α)=1.86×0.1×1.23=0.229(B)

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