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Abnormal Colligative Properties

3.0 × 10-3 kg...

Question

$3.0 \times 10^{- 3} k g$ of acetic acid is added to 500 mL of water. $23 %$ of acetic acid is dissociated. If Kf and density of water are $1.86 K k g m o l^{- 1}$ and 0.997 g/mL respectively. The depression in freezing point of acetic acid is :

0.227

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0.229

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0.231

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0.233

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Solution

The correct option is B 0.229
We have, $Δ T = K_{f} \times m o l a l i t y \times (1 + α) F o r a c e t i c a c i d : C H_{3} C O O H \leftrightarrow C H_{3} C O O^{-} + H^{+}$
1 0 0
$1 - α$ $α$ $α$
Given, $α = 0.23$ ;
$A l s o, m o l a l i t y = \frac{m o l e o f a c e t i c a c i d}{w e i g h t o f w a t e r i n k g}$
$= \frac{(3 \times 10^{- 3} \times 10^{3})}{{\frac{60 \times (500 \times 0.997)}{103}}} = 0.10 Δ T = K_{f} \times m o l a l i t y \times (1 + α) = 1.86 \times 0.1 \times 1.23 = 0.229 (B)$

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