Question

$3.01\times {10}^{23}$ molecules of elemental Sulphur will react with 0.5 mole of oxygen gas completely to produce

• A. $6.02\times {10}^{23}$ molecules of $S{O}_3$
• B. $6.02\times {10}^{23}$ molecules of $S{O}_2$
• C. $3.01\times {10}^{23}$ molecules of $S{O}_3$
• D. $3.01\times {10}^{23}$ molecules of $S{O}_2$

Answer 1

The correct option is D $3.01\times {10}^{23}$ molecules of $S{O}_2$

$\underset{\underset{\frac{1}{2}mole}{1mole}}{S}+\underset{\underset{\frac{1}{2}mole}{1mole}}{O_2}\to \underset{\underset{\frac{1}{2}mole}{1mole}}{S{O}_2}$
$3.01\times {10}^{23}0.5mole?$
$\therefore 3.01\times {10}^{23}$ molecules of $S{O}_2$ will be formed.