Question

$(3,-1)$ and $(-2,3)$ are two vertices of triangle. Circumcentre of triangle lie at the origin. Find the co-ordinates of third vertices.

Answer 1

$(3,-1),(-2,3)$ are vertices of origin

Let $(x,y)$ be third vertex

Circum center is given as $(0,0)$

$(\frac{3-2+x}{3},\frac{-1+3+y}{3})=(0,0)1+x=0,y+2=0x=-1,y=-2$

So the third vertex is $(-1,-2)$