(3, -1) is the image of the point P (-3,5) about the line ax + by + c = 0 find the value of −ab
The line PQ is perpendicular to L.R is a point on the line L and it is the mid point of P and Q.
To find −ab , we will first find the equation of L.
We can find one point (R) and the slope of the line L, (L is r to PQ)
1) Finding R
R ≡ (−3+30,5+12)
≡ (0,2)
2) Finding slope of PQ
m1=5−(−1)−3−3=−1
3) Finding slope of L
Let m2 be the slope of L
m1m2=−1
⇒ -1 × m2 = -1
⇒ m2=−1
4) Finding the equation of 2
y - 32 = 1 (x-0)
⇒ x - y + 2 = 0
5) Finding −ab
−ab=−1−1=1
−ab is the slope of the line ax + by + c = 0 . We can directly find it after getting the slope of PQ