Question

$3.12g$ of oxygen is adsorbed on $1.2g$ of platinum metal. The value of oxygen adsorbed per gram of the adsorbent at $1atm$ and $300K$ in $L$ is _______.
$[R=0.0821Latm{K}^{-1}mo{l}^{-1}]$

Answer 1

$\text{Moles of}{O}_2=\frac{3.12}{32}=0.0975mol$

$\text{Volume of}{O}_2=\frac{nRT}{P}=\frac{0.0975\times 0.0821\times 300}{1}=2.3985L\approx 2.4L$

$\text{Volume of}{O}_2\text{absorbed per gram of platinum}=\frac{2.4}{1.2}=2$