3, 15, ?, 63, 99, 143

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Solution

The correct option is B 35
The terms of the given series are $(2^{2} - 1), (4^{2} - 1), . . . . ., (8^{2} - 1), (10^{2} - 1), (12^{2} - 1)$ .
So, missing term = $(6^{2} - 1) - (36 - 1) = 35$ .

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