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Question

3.17gm of a substance was deposited by the flow of 0.1 mole of electrons. The equivalent weight of the substance is:

A
3.17
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B
0.317
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C
317
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D
31.7
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Solution

The correct option is B 31.7
Given,
3.17gm of substance was deposited by flow
0.1 mole of e
Charge of 1e=1.6×1019C
Now, 0.1 mole of e=0.1×6.023×1023es
Total amount of charge flown by 0.1 mole of e
=0.1×6.023×1023×1.6×1019C
=9636.8C
We know, 1F=96500C
9636.8C=9636.896500F=0.09986F
Also, F is required to deposit 1g equivalent of substance.
0.9986F=0.9986g equivalent
Now, g equivalent=WeightofsubstanceEquivalentWeightofit
0.9986=3.17Eq.Wt
Eq.Wt=3.170.99863.170.1=31.7

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