$3^{- 2}$ can be written as:

3^{2}

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\frac{1}{3^{- 2}}

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\frac{1}{3^{2}}

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\frac{- 2}{3}

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Solution

The correct option is C $\frac{1}{3^{2}}$
We know that $x^{a} x^{- a} = x^{a - a} = x^{0} = 1$

$\Rightarrow x^{- a} = \frac{1}{x^{a}}$

Here put $a = 2$ and $x = 3$ , we get $3^{- 2} = \frac{1}{3^{2}}$

Therefore option $C$ is correct

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