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Octet Rule

3.2 g sulphur...

Question

$3.2$ g sulphur combines with $3.2$ g of oxygen to form a compound in one set of conditions. In another set of conditions, $0.8$ g of sulphur combines with $1.2$ g of oxygen to form another compound. State the law illustrated by these chemical combinations.

Law of constant composition

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Law of reciprocal proportion

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Law of multiple proportion

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None of the above

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Solution

The correct option is B Law of multiple proportion
First case,
$3.2$ g of S combines with $3.2$ g of $O_{2}$ .
$1$ g of S combines with $1$ g of $O_{2}$ .
Second case,
$0.8$ g of S combines with $1.2$ g of $O_{2}$
$1$ g of S combines with $\frac{1.2}{0.8} = 1.5$ g of $O_{2}$
Thus, the ratio of the $O_{2}$ in both cases which combines with a fixed mass ( $1$ g) of $S = 1 : 1.5$ or $2 : 3$ , which is a simple whole number ratio and hence, the law of multiple proportion is verified.

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3.2 g sulphur combines with 3.2 g of oxygen to form a compound in one set of conditions. In another set of conditions, 0.8 g of sulphur combines with 1.2 g of oxygen to form another compound. State the law illustrated by these chemical combinations.

$3.2$ g sulphur combines with $3.2$ g of oxygen to form a compound in one set of conditions. In another set of conditions, $0.8$ g of sulphur combines with $1.2$ g of oxygen to form another compound. State the law illustrated by these chemical combinations.