Here 3(2 x)≥ 2(1 x) ⇒ 6 3x ≥ 2 2x ⇒ 3x +2x ≥ 2 6 ⇒ x ≤ 4 Dividing both sides by 1, we have x/ 1 lt; 4/ 1⇒ x ≤ 4 Thus the solution set is ( ∞, 4]. ...

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Law of Reciprocal

32- x ≥ 21- x

Question

$3 (2 - x) \geq 2 (1 - x)$

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Solution

Here $3 (2 - x) \geq 2 (1 - x)$

$\Rightarrow 6 - 3 x \geq 2 - 2 x \Rightarrow - 3 x + 2 x \geq 2 - 6$

$\Rightarrow - x \leq - 4$

Dividing both sides by -1, we have

$\frac{- x}{- 1} < \frac{- 4}{- 1} \Rightarrow x \leq 4$

Thus the solution set is $(- \infty, 4] .$

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