${(3 (230 + x))^{2}} = 492 a 04$ then find the value of $a$ .

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Solution

${{(3 (230 + x))}^{2}} = 492 a 04$
$\Rightarrow 9 {(230 + x)}^{2} = 492 a 04$
$\Rightarrow 492 a 04$ is divisible by $9$
$\Rightarrow 4 + 9 + 2 + a + 0 + 4 = 9 k$
$\Rightarrow 19 + a = 9 k$
$\Rightarrow a = 8 [k = 3]$

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