-3 - (-3) =

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(3 + 2 \sqrt{3})

x^{2} + 6 x - 3 = 0

x^{2} - 6 x - 3 = 0

x^{2} + 6 x + 3 = 0

x^{2} - 6 x + 3 = 0

\frac{x}{1} = \frac{y}{2} = \frac{z}{3} and \frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}

\frac{x}{1} = \frac{y}{2} = \frac{z}{3}

\frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}

Z_{1} = \sqrt[6]{\frac{1 - i}{1 + i \sqrt{3}}}; Z_{2} = \sqrt[6]{\frac{1 - i}{\sqrt{3} + i}}; Z_{3} = \sqrt[6]{\frac{1 + i}{\sqrt{3} - i}}

If z_{1} = 2 + i, z_{2} = 3 - i, z_{3} = - 5 + 2 i, z_{4} = - 6 - 4 i,

z_{1} + z_{2} + z_{3} + z_{4}

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