Question

$3.34g$ of an oxide (I=127) contains 2.54 g of iodine. Its formula will be:

• A. $I_2{O}_3$
• B. $I_2{O}_4$
• C. $I_2{O}_5$
• D. $I_2{O}_7$

Answer 1

The correct option is C $I_2{O}_5$

Mass of oxygen $=3.34-2.54$

$=0.80gm$

Let,the oxide be $I{O}_x$

$\therefore$ No. of moles of iodine $=\frac{2.54}{127}$

Moles of oxygen $=\frac{0.80}{16}$

$\therefore \frac{0.80}{16}=x\times \frac{2.54}{127}$

$\Rightarrow x=\frac{5}{2}$

$\therefore$ Oxide is $I{O}_{5/2}$ or $I_2{O}_5$