3 4 6 9 13 18 ____

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Solution

In this problem the difference between two consecutive terms is constantly increasing by 1
In shortcut the pattern is indicated as under

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Similar questions

Verify the following:

(i) $18 \times [9 + (- 7)] = 18 \times 9 + 18 \times (- 7)$

(ii) $(- 13) \times [(- 6) + (- 19)] = (- 13) \times (- 6) + (- 13) \times (- 19)$

\frac{9}{3} \div \frac{4}{6} \times \frac{13}{18} - \frac{3}{5} =

x \frac{13}{20}

Subtract :

(i) $\frac{3}{4}$ from $\frac{1}{3}$ (ii) $\frac{- 5}{6}$ from $\frac{1}{3}$ (iii) $\frac{- 8}{9}$ from $\frac{- 3}{5}$

(iv) $\frac{- 9}{7}$ from -1 (v) $\frac{- 18}{11}$ from 1 (vi) $\frac{- 13}{9}$ from 0

(vii) $\frac{- 32}{13}$ from $\frac{- 6}{5}$ (viii) -7 from $\frac{- 4}{7}$

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