3 - 47 x-1-2 x-1-x - 2-x-3 - 2

From (3/4)(7x 1) 2x (1 x)/2=x+3/2 I recommend multiplying everything by the lowest common denominator. That clears all the fractions in one step. Here the LCD i ...

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Byju's Answer

Standard VII

Mathematics

Integers

3 / 47 x-1-2 ...

Question

$\frac{3}{4} (7 x - 1) - (2 x - 1 - \frac{x}{2}) = x + \frac{3}{2}$

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Solution

Given that
$\frac{3}{4} (7 x - 1) - (2 x - 1 - \frac{x}{2}) = x + \frac{3}{2}$
or $\frac{3}{4} (7 x - 1) - (\frac{4 x - 2 - x}{2}) = \frac{2 x + 3}{2}$
or $\frac{3}{4} (7 x - 1) - 2 (\frac{4 x - 2 - x}{4}) = \frac{2 (2 x + 3)}{4}$
or $\frac{(21 x - 3)}{4} - (\frac{6 x - 4}{4}) = \frac{(4 x + 6)}{4}$
or $21 x - 3 - 6 x + 4 = 4 x + 6$
or $15 x + 1 = 4 x + 6$
or $11 x = 5$
or $x = \frac{5}{11}$

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Similar questions

Q. Solve :

\frac{3}{4} (7 x - 1) - (2 x - \frac{1 - x}{2}) = x + \frac{3}{2}

Q. The value of

x

\frac{3}{4} (7 x - 1) - (2 x - \frac{1 - x}{2}) = x + \frac{3}{2}

is ___________.

Q. Find the solution of given problem

\frac{3}{4} (7 x - 1) - (2 x - \frac{1 - x}{2}) = x + \frac{3}{2}

Q. On solving

31 x + 47 y = 15 and 47 x + 31 y = 63,

we get:
(a) x = 2, y = −1
(b) x = −2, y = 1
(c) x = 1, y = 2
(d) x = 3, y = −2

∣ ∣ ∣ ∣ \begin{matrix} x^{2} + 2 x & 2 x + 1 & 1 2 x + 1 & x + 2 & 1 3 & 3 & 1 \end{matrix} ∣ ∣ ∣ ∣ = {(x - 1)}^{3} .

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34(7x−1)−(2x−1−x2)=x+32

Given that 34(7x−1)−(2x−1−x2)=x+32 or 34(7x−1)−(4x−2−x2)=2x+32 or 34(7x−1)−2(4x−2−x4)=2(2x+3)4 or (21x−3)4−(6x−44)=(4x+6)4 or 21x−3−6x+4=4x+6 or 15x+1=4x+6or 11x=5or x=511

$\frac{3}{4} (7 x - 1) - (2 x - 1 - \frac{x}{2}) = x + \frac{3}{2}$