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Question

Question 9
3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are
(a) 6.68×1023
(b) 6.09×1022
(c) 6.022×1023
(d) 6.022×1021

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Solution

Sucrose molar mass = 144 + 22 + 176 = 342 g/mol

1 mol of sucrose contains = 11× NA atoms of oxygen,

where NA = 6.023×1023

0.01 mol of sucrose (C12H22O11) contains = 0.01 × 11 ×NA atoms of oxygen

= 0.11× NA atoms of oxygen

= 18 g/(1 × 2+ 16)gmol1

=18 g /18 gmol1

= 1mol

1mol of water (H2OH_2OH2O) contains 1 × NA atom of oxygen

Total number of oxygen atoms = Number of oxygen atoms from sucrose + Number of oxygen atoms from water

Total number of oxygen atoms = 0.11 NA + 1.0 NA = 1.11NA

Number of oxygen atoms in solution = 1.11 × Avogadro’s number

Number of oxygen atoms in solution = 1.11 × 6.022 ×1023

Number of oxygen atoms in solution = 6.68 × 1023


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