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Arrhenius Acid

3.45 g of a m...

Question

$3.45 g$ of a metallic carbonate were mixed with $240 m L$ of $N / 4 H C l$ . The excess acid was neutralised by $50 m L$ of $N / 5 K O H$ solution. Calculate the equivalent mass of the metal.

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Solution

Equivalent mass of metal carbonate
$= \frac{3.45 \times 4 \times 1000}{200} = 69$
Equivalent mass of metal $= 69 -$ Eq. mass of carbonate
$= (69 - 30) = 39$ .

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