$3.49$ g of ammonia at STP occupies volume of $4.48$ $d m^{3}$ calculate molar mass of ammonia.

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Solution

We can calculate the relative molar mass of the molecule.
Here volume is $4.48 d m^{3} = 4.48 L$
Now according to gas law, we know that the volume of one mole of gas $= 22.4 L$
$4.48 L$ of the ammonia gas takes $3.49 g r a m$
So $22.4 L$ of the gas take $= \frac{3.49 \times 22.4}{4.48} = 17.45 g r a m$
So relative molar mass of the ammonia gas is $17.45 g r a m$

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