3^(4x+1) = (27)^(x+1) 3^(4x+1) = (3)^3(x+1) We get #160; #160; 4x+1 = 3(x+1) Or #160; #160; 4x+1 = 3x+3 x = 2 ...

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34x+1=27x+1 f...

Question

$3^{4 x + 1} = (27)^{x + 1}$ find x.

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Solution

$3^{(4 x + 1)} = (27)^{(x + 1)}$
$3^{(4 x + 1)} = (3)^{3 (x + 1)}$
We get $4 x + 1 = 3 (x + 1)$
Or $4 x + 1 = 3 x + 3$
$⟹ x = 2$

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