$3$
$6$
$8$
$5$
$8$
$4$
$4$
$7$
$?$

6

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7

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Solution

The correct option is A $6$
Sum of $1^{s t}$ row= $3 + 6 + 8 = 17$
Sum of $2^{n d}$ row= $5 + 8 + 4 = 17$
Let $^{'} x^{'}$ be the missing term.
Sum of $3^{r d}$ row= $4 + 7 + x = 17$
$∴ x = 6$
Hence, option $A$ is the correct answer.

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Similar questions

Q. Which of the following will come next in the following series?

919829873987649876559876546987654

Q. In a shop, different sizes of shoes sold in a week are 7, 9, 8, 6, 7, 10, 6, 7, 8, 9, 11, 5, 6, 7, 8, 5, 9, 10, 9, 11, 12, 8, 3, 3, 5, 4, 6, 7, 4, 6, 7, 8, 8, 6, 9. What is the difference of the number between shoes sold of size 6 and size 7?

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

Q. The following data gives the marks of 20 students in Mathematics (X) and statistics (Y), each out of 10, expressed as (x, y). Construct an ungrouped frequency distribution, considering single numbers as a class:

(2, 7), (3, 8), (4, 9), (2, 8), (5, 6), (5, 7), (4, 9), (3, 8), (4, 8), (2, 9), (3, 8), (4, 8), (5, 6), (4, 7),

(4, 7), (4, 6), (5, 6), (5, 7), (4, 6), (5, 5).

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36858447?

The correct option is A 6Sum of 1st row= 3+6+8=17Sum of 2nd row= 5+8+4=17Let ′x′ be the missing term.Sum of 3rd row= 4+7+x=17∴x=6Hence, option A is the correct answer.

$3$
$6$
$8$
$5$
$8$
$4$
$4$
$7$
$?$

The correct option is A $6$
Sum of $1^{s t}$ row= $3 + 6 + 8 = 17$
Sum of $2^{n d}$ row= $5 + 8 + 4 = 17$
Let $^{'} x^{'}$ be the missing term.
Sum of $3^{r d}$ row= $4 + 7 + x = 17$
$∴ x = 6$
Hence, option $A$ is the correct answer.