Question

3, 6 and 5 are in continued proportion

• A. True
• B. False

Answer 1

The correct option is B

False

Three terms a , b , c are said to be in continued proportion , if a: b = b:c

i.e $b^2=ac$

Hence, if 3 : 6 : 5 are in proportion , then $\frac{3}{6}$ = $\frac{6}{5}$

We have $6^2=36$

$3\times 5$ = 15

Since $36\ne 15$ , 3 , 6 and 5 are not in continued proportion