The correct option is C Not defined Given, [( 3) + 6] ÷ nbsp;[( 3) + 3] nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; = 3 ÷ 0 ∵ nbsp;Any number n ...

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Byju's Answer

Standard VI

Mathematics

BODMAS

[-3+6] ÷[-3+3...

Question

[(-3) + 6] $\div$ [(-3) + 3] =

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Not defined

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Solution

The correct option is D
Not defined

Given, [(-3) + 6] $\div$ [(-3) + 3]
= 3 $\div$ 0
$∵$ Any number divided by 0 is not defined
$\Rightarrow$ 3 $\div$ 0 = Not defined.

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Similar questions

Given a = 6 + √3
⇒ (1/a) = 1 / (6 + √3)
Multiply and divide by (6 − √3)
⇒ (1/a) = (6− √3) / [(6 + √3)(6 − √3)]
⇒ (1/a) = (6 − √3) / [36 − 3]
⇒ (1/a) = (6− √3)/33
∴ a - (1/a) = (6 + √3) -(6 − √3)/33
= [33(6 + √3) - (6 - √3)]/33
= [32*6 + 34*√3]/33
= [192 + 34√3]/33

Answer : [192 + 34√3]/33

Why does 1/a come above

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Q. Find the value

y = \sqrt[3]{6 + \sqrt[3]{6 + \sqrt[3]{6 \sqrt[3]{6 + . . . . \infty}}}}

Question 6

Q. Solve

\frac{\sqrt{6}}{\sqrt{2} + \sqrt{3}} + \frac{3 \sqrt{2}}{\sqrt{6} + \sqrt{3}} + \frac{4 \sqrt{3}}{\sqrt{6} + \sqrt{2}}

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[(-3) + 6] ÷ [(-3) + 3] =

The correct option is D Not defined Given, [(-3) + 6] ÷ [(-3) + 3] = 3 ÷ 0 ∵ Any number divided by 0 is not defined ⇒ 3 ÷ 0 = Not defined.

[(-3) + 6] $\div$ [(-3) + 3] =

The correct option is D
Not defined

Given, [(-3) + 6] $\div$ [(-3) + 3]
= 3 $\div$ 0
$∵$ Any number divided by 0 is not defined
$\Rightarrow$ 3 $\div$ 0 = Not defined.