3.6 g $O_{2}$ is adsorbed in 1.2 g of metal powder. What volume of $O_{2}$ adsorbed per gram of the adsorbent at STP?

0.19 L

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1 L

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2.1 L

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3.1 L

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Solution

The correct option is B 2.1 L
$3.6 g$ of $O_{2}$ is a adsorbed in $1.2 g$ of metal powder.
Mass of $O_{2}$ adsorbed per $g$ of adsorbent $= \frac{3.6}{1.2} = 3 g$ .
$32 g$ of $O_{2}$ occupies $= \frac{3 \times 224}{32} = 2.1 L$

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