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Question

3.6 g of oxygen is adsorbed on 1.2 g of a metal powder. What volume of oxygen is adsorbed per gram of the adsorbent at 1 atm and 300 K?

A
0.19 Lg1
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B
1 Lg1
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C
2.31 Lg1
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D
3.14 Lg1
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Solution

The correct option is C 2.31 Lg1
Mass of O2 adsorbed per gram of adsorbent =3.61.2= 3
Number of moles of O2 per gram of adsorbent = 332
Volume of O2 per gram of adsorbent =332×(0.0821)×(300)1
=2.31 Lg1
You can use the approximation that R112 L atm/mol K and you get the answer to be 2.34

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