Question

3.6 gm of $O_2$ is adsorbed on 1.2 gr of metal powder. What volume of $O_2$ adsorbed per gram of the absorbant at 1 atm and 273K?

• A. 2.1
• B. 0.19
• C. 1
• D. None

Answer 1

The correct option is A 2.1

$1.2g\to 3.6g$ oxygen
$1g\to \frac{3.6}{1.2}=3g$
$PV=\frac{x}{M}\times RT$
$1\times V=\frac{3}{32}\times 0.0821\times 273$
$V=2.1L$