Question

$3.6$ gram of oxygen is adsorbed on $1.2$g of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at $1atm$ and $273K$?

• A. $0.19L{g}^{-1}$
• B. $1L{g}^{-1}$
• C. $2.1L{g}^{-1}$
• D. None of these

Answer 1

The correct option is C $2.1L{g}^{-1}$

Mass of oxygen adsorbed per gram of metal powder $=\frac{3.6}{1.2}g=3g=m$

By ideal gas equation, $PV=nRT\therefore V=\frac{mRT}{MP}=\frac{3\times 273\times 0.0821}{32\times 1atm}=2.1L{g}^{-1}$

Option $C$ is the correct answer.