By the properties of the exponent, we know that a^x÷a^y = a^x yBy using the above property 3^7÷3^4 = 3^7 4Hence, the correct answer is 3^7 4. ...

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Standard VIII

Mathematics

Repeated Exponentiation

37÷34 = . 37/...

Question

$3^{7} \div 3^{4} =_________.$ $(3^{\frac{7}{4}} / 3^{7 - 4})$

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Solution

By the properties of the exponent, we know that -
$a^{x} \div a^{y} = a^{x - y}$
By using the above property -
$3^{7} \div 3^{4} = 3^{7 - 4}$
Hence, the correct answer is $3^{7 - 4}$ .

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Similar questions

Q. Choose the right answer from the options given after every question.

{[{(\frac{3}{7})}^{- 3}]}^{4}

= ................

(i)

{(\frac{3}{7})}^{- 7}

(ii)

{(\frac{3}{7})}^{- 10}

(iii)

{(\frac{7}{3})}^{12}

(iv)

{(\frac{3}{7})}^{20}

Q. If α and β are the roots of

4 x^{2} + 3 x + 7 = 0

, then the value of

\frac{1}{α} + \frac{1}{β}

is
(a)

\frac{4}{7}

(b)

- \frac{3}{7}

(c)

\frac{3}{7}

(d)

- \frac{3}{4}

Complete the table below.

$\begin{matrix} Sr. No. & Indices(Numbers in Index Form) & Base & Index & Multiplication Form & Value (i) & 3^{4} & 3 & 4 & 3 \times 3 \times 3 \times 3 & 81 (i i) & 16^{3} (i i i) & (- 8) & 2 (i v) & 37 \times 37 \times 37 \times 37 & 1874161 (v) & (- 13)^{4} \end{matrix}$

Q. 4. 3(7 i7) (7+ i7)

Q. Simplify :

\frac{5 + \sqrt{3}}{7 - 4 \sqrt{3}} - \frac{5 - \sqrt{3}}{7 + 4 \sqrt{3}}

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37÷34=_________. (374/37-4)

By the properties of the exponent, we know that -ax÷ay=ax-yBy using the above property -37÷34=37-4Hence, the correct answer is 37-4.

$3^{7} \div 3^{4} =_________.$ $(3^{\frac{7}{4}} / 3^{7 - 4})$

By the properties of the exponent, we know that -
$a^{x} \div a^{y} = a^{x - y}$
By using the above property -
$3^{7} \div 3^{4} = 3^{7 - 4}$
Hence, the correct answer is $3^{7 - 4}$ .