3+√7/3-√7=a+b√7

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Solution

Multiplied mumerator & denominator by 3root+7
(3+root7) (3+root7)/( 3-root7)(3+root7)=a+b root7
(3+root7)^2 /(3)^2 -(root7)^2= a+b root7
(3^2+ root7^2+2×3×root7)/ 9-7=a+b root7
9+7+6root7/ 2=a+b root7
16+6root7 /2=a+b root7
8+3root7=a+b root7
on comparing
a= 8 & b=3

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Similar questions

$(7 a^{2} - 63 b^{2}) = ? (a) (7 a - 9 b) (9 a + 7 b) (b) (7 a - 9 b) (7 a + 9 b) (c) 9 (a - 3 b) (a + 3 b) (d) 7 (a - 3 b) (a + 3 b)$

What is the product of $(a + b)$ and $7 a^{2}$ $b^{2}$ ?

a + b + c = 3

a > 0, b > 0, c > 0

a^{2} b^{3} c^{2}

\frac{3 a + 7 b}{3 a - 7 b} = \frac{4}{3}

\frac{3 a^{2} - 7 b^{2}}{3 a^{2} + 7 b^{2}}

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