3.7g of oxide of a metal was heated with charcoal. The liberated carbon dioxide was absorbed in NaOH solution and weighed 1.0g. If the specific gravity of the metal is 0.095cal/g the exact atomic mass of the metal is
A
170.8
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B
32.7
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C
67.37
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D
65.4
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Solution
The correct option is D65.4 Weight of CO2 = 1.0g Weight of oxygen in oxide = Weight of oxygen in Carbon dioxide =3244×1=0.727g Mass of metal oxide = 3.7g, Mass of oxygen = 0.72g, so mass of metal = 3.7-0.72 = 2.973g. Eq. Mass of metal =2.9730.727×8=32.7 App. Atomic mass =6.4Sp.heat=6.40.095=67.36 n=App.AtomicmassEq.mass=67.3632.7≈2 Exact atomic mass = 32.7 × 2 = 65.4