-3 -8-1-7- 1-7-3 -8 is an example to show that

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Commutative Property of Rational Numbers

-3 /8+1/7= 1/...

Question

$\frac{- 3}{8} + \frac{1}{7} = \frac{1}{7} + \frac{- 3}{8}$ is an example to show that

addition of rational numbers is commutative.

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rational numbers are closed under addition.

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addition of rational numbers is associative.

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rational numbers are distributive under addition.

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Solution

The correct option is A
addition of rational numbers is commutative.

For rational numbers, addition and multiplication are commutative.
Commutative law of addition: $a + b = b + a$
Commutative law of multiplication: $a \times b = b \times a$
Commutative property
1. Addition
If any two numbers are added for example $a$ and $b$ the $a + b = b + a$
So addition is the commutative property for rational numbers.
2. Subtraction
For two rational numbers $a$ and $b$ , $a - b \neq b - a$
It is not commutative for rational numbers.
3. Multiplication
For any two rational numbers $a$ and $b$ , $a * b = b * a$
Multiplication is commutative for rational numbers.
Hence, option A is correct.

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Similar questions

Question 5
$- \frac{3}{8} + \frac{1}{7} = \frac{1}{7} + (\frac{- 3}{8})$ is an example to show that
(a) addition of rational numbers is commutative.
(b) rational numbers are closed under addition.
(c) addition of rational number is associative.
(d) rational numbers are distributive under addition

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

Solve:

(i) $2 - \frac{3}{5}$

(ii) $4 + \frac{7}{8}$

(iii) $\frac{3}{5} + \frac{2}{7}$

(iv) $\frac{9}{11} - \frac{4}{15}$

(v) $\frac{7}{10} + \frac{2}{5} + \frac{3}{2}$

(vi) $2 \frac{2}{3} + 3 \frac{1}{2}$

(vii) $8 \frac{1}{2} - 3 \frac{5}{8}$

If $f = \frac{x}{1 + x^{2}} + \frac{1}{3} {(\frac{x}{1 + x^{2}})}^{3} + \frac{1}{5} {(\frac{x}{1 + x^{2}})}^{5} + . . .$ to $\infty$ and $g = x - \frac{2}{3} x^{3} + \frac{1}{5} x^{5} + \frac{1}{7} x^{7} - \frac{2}{9} x^{9} + . . .$ , then $f = d \times g$ . Find 4d.

Determine whether the following numbers are in proportion or not $:$

$\frac{1}{3}, \frac{1}{4}, \frac{1}{6}, \frac{1}{7}$

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-38+17=17+-38 is an example to show that

$\frac{- 3}{8} + \frac{1}{7} = \frac{1}{7} + \frac{- 3}{8}$ is an example to show that